Tom Kelliher, CS 220
Sept. 30, 2009
Look over the SPIM S20 manual on the course web site.
Control structures in MIPS assembly.
More MIPS programming.
Things to notice:
syscall. Exit from your program:
li $v0, 10 syscall
.globl.
#include <stdio.h>
int main()
{
char *prmpt1 = "How many inputs? ";
char *prmpt2 = "Next input: ";
char *result = "The sum is ";
char *nl = "\n";
int n;
int sum;
int temp;
printf("%s", prmpt1);
scanf("%d", &n);
sum = 0;
while (n > 0)
{
printf("%s", prmpt2);
scanf("%d", &temp);
sum = sum + temp;
n = n - 1;
}
printf("%s", result);
printf("%d", sum);
printf("%s", nl);
return 0;
}
# addn.spim
# Input: A number of inputs, n, and n integers.
# Output: The sum of the n inputs.
# Demonstrates reading and writing integers.
# Register usage:
# $t0: how many integers remain to be read.
# $t1: sum of the integers read so far.
.data # Constants.
prmpt1: .asciiz "How many inputs? "
prmpt2: .asciiz "Next input: "
sum: .asciiz "The sum is "
nl: .asciiz "\n"
.text # Main.
.globl main
main: li $v0, 4 # Syscall to print prompt string.
la $a0, prmpt1
syscall
li $v0, 5 # Syscall to read an integer.
syscall # Result returned in $v0.
move $t0, $v0 # n stored in $t0.
li $t1, 0 # sum stored in $t1 -- clear it.
.globl while
while: blez $t0, endwhile # Read n integers.
li $v0, 4 # Prompt for next integer
la $a0, prmpt2
syscall
li $v0, 5 # Read next integer.
syscall
add $t1, $t1, $v0 # Increase sum by new input.
sub $t0, $t0, 1 # Decrement n.
b while
endwhile: li $v0, 4 # Print result string.
la $a0, sum
syscall
move $a0, $t1 # Print sum.
li $v0, 1
syscall
li $v0, 4 # Print a newline character.
la $a0, nl
syscall
li $v0, 10 # Syscall to exit.
syscall
See lab handout.