Tom Kelliher, CS23
Mar. 10, 1996
Guessing at a solution and backing up out of a deadend.
Place 4 Queens on a 4 by 4 chess board such that no Queen can be attacked by another.
What's recursive about this?
Try it.
Pseudocode:
int place(int column) { int row = 1; if (column > 4) return success; while (row < 5) { if safe(row, column) // check that no attacks can occur { place queen at board[row][column]; if (place(column + 1) == success) return success; pick up queen at board[row][column]; } ++row; } return failure; }
How would you find a route through the maze?
Representation of the maze?
Pseudocode:
int search(block) { mark block "path"; if block is goal return success; if block to north exists and is unvisited if (search(block to north) == success) return success; if block to east exists and is unvisited if (search(block to east) == success) return success; if block to south exists and is unvisited if (search(block to south) == success) return success; if block to west exists and is unvisited if (search(block to west) == success) return success; mark block "no path"; return failure; }
A language is a set of strings of symbols. The C++ language is the set of strings of symbols accepted by a C++ compiler.
A grammar is a set of rules describing a language. The rules tell you how to build a string belonging to the language.
Consider a simple grammar:
<expr>=<term>{+|-<term>} <term>=factor{*|/<factor>} <factor>=(<expr>)|<letter> <letter>=a|b|c|...|zWhat language is described?
Extended Backus-Naur form (EBNF):
Expressing associativity, precedence?
Relationship between a production and a recursive set of functions?
/********************************************************************** * expr.cc --- Convert infix expression to postfix form and indicate * if the infix expression was properly formed. * * This is a recursive descent parser, implementing the following * grammar: * <expr>=<term>{+|-<term>} * <term>=<factor>{*|/<factor} * <factor>=(<expr>)|<letter> * <letter>=a|b|c|...|z **********************************************************************/ #include <iostream.h> #include <ctype.h> void GetToken(void); int Expression(void); int Term(void); int Factor(void); char Token; // Next character in the input stream --- one character // lookahead. /********************************************************************** * main() **********************************************************************/ int main() { cout << "Type return on an otherwise empty line to exit.\n\n"; while (1) { cout << "Expression: "; // Read infix expression. GetToken(); if (Token == '\n') // return 0; // Parse the expression; if successful and we've read the entire line, // then we saw a valid expression if (Expression() && Token == '\n') cout << "\nValid expression\n"; else { cout << "\nInvalid expression\n"; while (Token != '\n') // finish off the line GetToken(); } } return 0; } /********************************************************************** * Expression() --- Parse an expression * This implements the production <expr>=<term>{+|-<term>} **********************************************************************/ int Expression(void) { char Operator; if (!Term()) return 0; while (Token == '+' || Token == '-') { Operator = Token; GetToken(); // Remove operator from input stream. if (!Term()) return 0; cout << Operator; // The operator is output following the // operands --- converting the expression // to postfix. } return 1; } /********************************************************************** * Term() --- Parse an term * This implements the production <term>=<factor>{*|/<factor>} **********************************************************************/ int Term(void) { char Operator; if (!Factor()) return 0; while (Token == '*' || Token == '/') { Operator = Token; GetToken(); // Remove operator from input stream. if (!Factor()) return 0; cout << Operator; // Postfix formulation. } return 1; } /********************************************************************** * Factor() --- Parse an factor * This implements the productions <factor>=(<expr>)|<letter> * and <letter>=a|b|c|...|z **********************************************************************/ int Factor(void) { if (islower(Token)) { cout << Token; // Operands output immediately GetToken(); // Remove operand from input stream. return 1; } else if (Token == '(') { GetToken(); // Remove '(' from input stream. if (Expression() && Token == ')') // check for parenthesized // expression { GetToken(); // Remove ')' from input stream. return 1; } else return 0; } else return 0; } /********************************************************************** * GetToken() --- read the next token from cin into the global variable * Token. **********************************************************************/ void GetToken(void) { cin.get(Token); }
Actions associated with each production?
Could we evaluate expressions?
Could we add an assignment operator?